[ home ]
|
Variation (least action) principle |
General Relativity. Note:
« 6
»
|
Unnamed Web page
The differential dg of the determinant of the metric
tensor gab is dg=ggabdgab=−ggabdgab
Variational principle (= least action principle)
The laws of physics can be formulated as a vanishing variation,
δ S=0, of some action S=∫ LdΩ, where
L is called Lagrangian (density). Examples:
- Nonrelativistic particle: L=T−V, where T= 1/2 mv2 is
the particle's kinetic energy and V is its potential energy.
- Free relativistic particle: S = −mc∫ ds.
- Electromagnetic field: Lem = − 1/16π FabFab ∝
− 1/8π Aa,bAa,b.
- Relativistic particle with charge q in the
electromagnetic field Aa: = −mc∫ ds − q∫ Aadxa
+Lem
The action for the matter in the presence of a gravitational field
If the action S for a physical system in special relativity is
Sm = ∫ L dΩ, then in a gravitational field it must have
basically the same form,
Sm = ∫ L[g]√[−g]dΩ,
where the notation L[g] indicates that all contractions in the Lagrangian
L must be written explicitely through the metric tensor gab.
Variation of the action with respect to gab and the energy−momentum
tensor of matter
The variation δ Sm of the matter action due to a variation
δ gab is given in terms of a symmetric tensor Tab,
δ Sm = 1/2 ∫ Tab δ gab √[−g] dΩ
= − 1/2 ∫ Tab δ gab √[−g] dΩ,
where
1/2 √[−g]Tab = δ(√[−g]L)/δgab .
This tensor satisfies the equation Tab;b=0 which in a flat space
turns into the energy−momentum conservation equation Tab,b=0 and
we thus deduce that it must be the energy−momentum tensor.
Exercises
- Prove, that Γaba=(ln√[−g]),b (where
,b= ∂/∂ xb ).
- Prove, that √[−g]Aa;a=(√[−g]Aa),a (where
;b= D/∂ xb ).
- The lagrangian density for the electromagnetic field is
L = − 1/16π FabFab.
Calculate the corresponding energy−momentum tensor using
1/2 √[−g] Tab =
∂√[−g]L/∂gab .
Answer:
Tab = 1/4π (−FacFbc +
1/4 FcdFcdgab)
Copyleft
©
2005 D.V.Fedorov
(fedorov @ phys au dk)