\begin{displaymath}\Delta\alpha = (50.37'' (\cos\epsilon + \sin\epsilon \sin\alpha \tan
\delta) - 0.11'') \Delta t(year)
\end{displaymath} (1)


\begin{displaymath}\Delta\delta = 50.37''(\sin\epsilon \cos\alpha) \Delta t(year)
\end{displaymath} (2)

Søren Frandsen
2007-02-01