Newtonian limit: slow motion in weak fields

Newtonian gravitation

The Newton's law of gravitation states that two bodies with masses m and M located at a relative distance r attract each other with the force
F=G mM

r2
,
(1)
where G ≈ 6.67×10−11Nm2kg−2 is the gravitational constant measured by Cavendish.
In other words a distribution of masses with density μ creates a gravitational potential φ([(r)\vec]) which satisfies the Poisson equation
∆φ = 4πGμ,
(2)
and a test body m in the gravitational potential φ is affected by a force

F
 
=−m


 
φ.
(3)
The last equation can be cast into a variational form with the action
S=
dt
mc2+ 1

2
mv2mφ
= −mc
dt
c v2

2c
+ φ

c

.
(4)
Comparing with S=−mcds we get (in the limit c→∞)
ds2=
1+

c2

c2dt2d

r
 
2
 
.
(5)
In other words in the Newtonian limit the metric tensor can be approximated1 by gabab+hab (where ηab is the Minkowski metric tensor and hab is a small correction) where the g00 component is
g00=1+

c2
.
(6)

Newtonian limit of general relativity

In this limit all fields are weak and all velocities are small. Only the 00 component of the energy-momentum tensor is non-vanishing, T00=μ where μ is the mass density of the matter. Therefore we shall only consider the 00 component of the Einstein's equation, R00=κ(T00−[1/2]g00T).
In the Newtonian limit g00=1 + 2φ, Γα00=−φ, R00=−φ=∆φ, where α = 1,2,3. The Einstein equation thus turns into the the Poisson's equation ∆φ = [1/2]κμ which is equivalent to the Newtonian theory if we put κ = [(8πG)/(c4)].

Gravitational waves.

In a weak gravitational field the space-time is almost flat and the metric tensor gab is equal to the flat metric ηab plus a small correction hab, gab = ηab+hab. The Riemann tensor to the lowest order in hab is
Rabcd = 1

2
(had,bc + hbc,adhac,bdhbd,ac).
(7)
If we choose coordinates such that (hab − [1/2]hδab),b=0, the Ricci tensor is simply
Rab = − 1

2
hab,c,c
(8)
and the vacuum Einstein's equations turn into the ordinary wave equations

2

t2
− ∆
hab = 0.
(9)
The intensity of gravitational radiation by a system of slowly moving bodies is determined by its quadrupole moment Dαβ
dE

dt
= G

45c5
(D"′αβ)2
(10)

Exercises

  1. Calculate the energy-momentum tensor Tab for a particle of mass m with the action S=−mds. Hint: calculate the variation of the action with respect to δgab and represent it in the form δS = −1/2Tabδgabds.
  2. In the Minkowski space consider a scalar field ϕ with action
    S =
    d
    1

    2
    ϕ,aϕ,a 1

    2
    m2ϕ2
    and calculate its "translation-invariance" energy-momentum tensor,
    Tab=L

    ∂ϕ,a
    ϕ,bLδab  .
    Rewrite the action in a generally covariant form and calculate its "metric-derivative" energy-momentum tensor,
    1

    2


     

    g
     
    Tab =
    δ(

     

    g
     
    L)

    δgab
      .

Footnotes:

1 where we have neglected the terms gαβ,  αβ = 1,2,3 since their contribution to ds2 is not multiplied by c2 and is thus neglidible compared to the contribution from g00.


File translated from TEX by TTH, version 3.77.
On 6 Oct 2007, 00:05.