[Home] |
Introduction to General Relativity. Note
« 2
»
|
Constantly accelerated elevator
Let the coordinates inside the elevator be (τ,ξ) such that τ is
the time inside the elevator and ξ is the distance from the floor. An
observer in the outer space uses Cartesian grid (t,x). If the floor of
the elevator moves with constant acceleration g the transformation
between these two frames is
x = (ξ+1/g) cosh( τ/(ξ+1/g) )-1/g,
t = (ξ+1/g) sinh( τ/(ξ+1/g) ). |
With new coordinates gη=τ/(ξ+1/g) and ρ=ξ+1/g
the transformation law simplifies
x = ρ cosh(gη)-1/g,
t = ρ sinh(gη). |
We notice important effects in the accelerated frame:
- The elevator coordinates are curved:
ds2 = dt2 - dx2 = (gρ)2dη2 - dρ2
- The local clock rate in the elevator varies with height:
ds2|dρ=0 = (gρ)2dη2
- Equal η lines converge towards the horizons -- the
boundaries that separate the part of the total space-time unavailable for
the observer in the elevator.
The equivalence principle tells that all these effects must as well
be present in gravitational fields.
Curved coordinates
(d'Inverno: Chapters 5,6; t'Hooft: Chapters 4,5)
A set of four quantities Aa (a=0,1,2,3) is called a contravariant
vector if under a transformation of coordinates x→x'(x) it
transforms as coordinate differentials dxa, that is:
Aa = (dxa/dx'b)A'b.
A set of four quantities Aa (a=0,1,2,3) is called a covariant
vector if under a transformation of coordinates x→x'(x) it
transforms as derivatives of a scalar dφ/dxa, that is:
Aa = (dx'b/dxa)A'b.
The scalar product AaBa≡∑aAaBa is invariant
under coordinate transformation
AaBa = A'aB'a
Exercises
-
Consider our constantly accelerated
elevator with the coordinates (η,ρ) and the
reference frame (t,x). With flat coordinates (t,x) the
trajectory x(t) of a free moving body satisfies the equation
d2x/dt2=0. What are the corresponding equations
for the free moving body in the internal (curved) coordinates
(η,ρ) ?
Hints:
-
Instead of x(t) consider a parametric description of the
curve, (t(s),x(s)), with the corresponding system of equations
d2x/ds2=0, d2t/ds2=0.
-
In this system of equations perform a substitution of variables
x=ρ cosh(gη)-1/g,
t=ρ sinh(gη).
-
Make suitable linear combinations of the equations to reduce them
to the canonical (geodesic) form as in d'Inverno,
eq.(6.37).
- Estimate the difference between the clock rates at the bottom and at
the top of the mount Everest in the Great Himalayas.
Copyleft
©
2003 D.V.Fedorov
(fedorov@ifa.au.dk)