fermion: u in the final state, u in the initial state
antifermion: v in the final state, v in the initial state
photon: √(4π)/√(2ω)εμ
vector: 1/√(2ω)εμ
Propogators
scalar: i/k2-μ2+i0
spinor: i/pγ-m+i0 = i[ pγ+m/p2-m2+i0 ]
electromagnetic: 4π -igμν/k2+i0
massive vector:
-i(gμν-kμkν/m2)/k2-μ2+i0
Exercises
Consider the interaction Lagrangian L=-gψγ5ψφ
between fermions ψ with mass m and neutral pseudoscalar particles φ with
mass μ. The lowest order matrix element of the elastic scattering of
fermions in the nonrelativistic limit is
Mfi(q) = (g2/m2)φ1+φ2+
((s1q)(s2q)/q2+μ2)
φ2φ1 .
As we showed the nonrelativistic potential V(r) is simply a Fourie
transform of the scattering amplitude
V(r) = -∫ d3q/(2π)3 Mfi(q) e-iqr.
Exercise: perform this Fourie transform and find the so called "one
boson exchange potential" (OBEP).
Hint: use the assumption
∫ d3q/(2π)3qjqk/q2+μ2 e-iqr =
A(r)δjk +
B(r)rjrk/r2
and find A(r) and B(r).
Answer:
A = μ2/4πexp(-μr)/r
(1/μr+1/(μr)2)
B = - μ2/4πexp(-μr)/r
(1 + 3/μr + 3/(μr)2)